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3x^2-48x=-192
We move all terms to the left:
3x^2-48x-(-192)=0
We add all the numbers together, and all the variables
3x^2-48x+192=0
a = 3; b = -48; c = +192;
Δ = b2-4ac
Δ = -482-4·3·192
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{48}{6}=8$
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